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 Re:The Consonant Nucleus  submitted:
2019/04/14 11:12:11 revised: 2019/04/20 09:28:55 

Briefly ...
The reason for the reference tone 'A' is because the derivation of the vectors all began from the tonal center of 'A'. However, as the vector developes into it's final form the tonic shifts to a new tone.
How do I know that? Because the raw interval clusters presented here must be rendered into their prime forms before the vector can be determined. At that point the new tonic becomes manifest.
The tonic for the 1st cluster is 'B'; the 2nd cluster is 'D#'; the 3rd cluster is 'C' and the last cluster is 'F'.
Now, any group of notes containing (6) different elements, as in the 1st cluster, contains (15) intervals. It doesn't matter what the notes are, or how you wish to label 'em.
For instance, a (6) element 'C11 chord ... c e g Bb d f ... contains (15) intervals. The 2nd cluster in the example has (6) elements as well, also producing (15) intervals, but with a different vector.
The vector clarifies the intervals exact nature and number, and that's why it's important.
Case in point, the vector for the 1st cluster is <143250>. What does that mean? It means that that (6) element cluster contains: (1) sharp dissonance (4) soft dissonance (5) imperfect consonants (5) perfect consonants, and no tritones.
The notes can be arranged in any order, the interval content is always the same, ie vector. 










 
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